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Kamala Harris is known to love Venn diagrams and would be cringing hard at this.

For reference, circles in Venn (Euler) diagrams are sets of objects with a certain property. Select objects are shown inside or outside of each circle depending on whether they belong to the set.
A good example is xkcd 2962:
Hard to imagine political rhetoric more microtargeted at me than 'I love Venn diagrams. I really do, I love Venn diagrams. It's just something about those three circles.'

    • bobzilla@lemmy.world
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      1 month ago

      Maybe I should ask OP who it is they’re saying is confidently incorrect? I originally thought that they were saying Oliver was incorrect, but your response makes me wonder if they meant the Trump campaign response was incorrect.

      Basically, I just want clarification.

    • ChaoticNeutralCzech@feddit.orgOP
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      1 month ago

      I’m not saying either is good use of Venn diagrams (as opposed to the provided xkcd comic). A better “mathematical” way to express the relation is simply “KAMA + BLA = KAMABLA” (yes, the mathematical sign “+” is not used for concatenation in math but you get the point).

      The tweet would work if we assume:

      • Left set A contains words that include “KAMA”, notably “KAMA” itself
      • Right set B contains words that include “BLA”, notably “BLA” itself
        • Their intersection A ∩ B contains words that belong to both sets, notably “KAMABLA”.

      Is it a technically correct Venn diagram? I’d say it could be, given the above weird assumptions.
      Is a Venn diagram the correct tool for the job? No.

      As for JO’s example with sea creatures: if we assume

      • A is a set of dolphins
      • B is a set of sharks
        • their intersection is an empty set: A ∩ B = { } because no dolphins are sharks

      JO’s example might work if

      • A was a set of properties of dolphins
      • B was a set of properties of sharks
        • their intersection includes “lives in the ocean”: A ∩ B = {“lives in the ocean”, …} because “lives in the ocean” is both a property of dolphins and a property of sharks

      However, this essentially turns around the convention “sets are defined by properties and include objects” to “sets are defined by objects and include their properties”, which is in my opinion even more cringey than considering “words containing ‘BLA’” a notable set. (From a mathematical standpoint. The entire “Kamabla” thing is pure cringe in the practical sense.)

      • ccunning@lemmy.world
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        1 month ago

        I think this is a good explanation of why JO is wrong, which I was not expecting.

        As for JO’s example with sea creatures: if we assume

        • A is a set of dolphins
        • B is a set of sharks
          • their intersection is an empty set: A ∩ B = { } because no dolphins are sharks

        This was my exact thought as I was watching but totally let it pass when he gave his “solution” without another thought before now.

        However I still don’t think the tweet works. Your logic is sound but the diagram would need to label sets A and B with “Words that include…”

        Of course that would just further expose it as unfunny and pointless.

        ETA: I notice you edited the comment while I was replying. Hoping you didn’t change the substance too much - I don’t have time at the moment to figure out what changed and see if my response still applies 😅🤞

        • tobogganablaze@lemmus.org
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          1 month ago

          You have two strings and in the overlap you have the concatenated string formed from the parts. Again, not useful but a totally valid interpretation.

          So … can you actually explain why you think it is incorrect or is snarky comments all you got?

          • ChaoticNeutralCzech@feddit.orgOP
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            1 month ago

            That picture does not make it clear that the labels refer to regions, not elements. A clearer explanation of set operators is the following:

            Set worksheet

            1. B (Set B)
            2. A ∪ B (Union of A and B)
            3. A (Set A)
            4. A \ B (A minus B; notation varies)
            5. B \ A (B minus A)
            6. A ∩ B (Intersection of A and B)